Optimal. Leaf size=346 \[ -\frac {(d+e x)^{11/2}}{4 b (a+b x)^3 \sqrt {a^2+2 a b x+b^2 x^2}}-\frac {11 e (d+e x)^{9/2}}{24 b^2 (a+b x)^2 \sqrt {a^2+2 a b x+b^2 x^2}}-\frac {1155 e^4 (a+b x) (b d-a e)^{3/2} \tanh ^{-1}\left (\frac {\sqrt {b} \sqrt {d+e x}}{\sqrt {b d-a e}}\right )}{64 b^{13/2} \sqrt {a^2+2 a b x+b^2 x^2}}+\frac {1155 e^4 (a+b x) \sqrt {d+e x} (b d-a e)}{64 b^6 \sqrt {a^2+2 a b x+b^2 x^2}}+\frac {385 e^4 (a+b x) (d+e x)^{3/2}}{64 b^5 \sqrt {a^2+2 a b x+b^2 x^2}}-\frac {231 e^3 (d+e x)^{5/2}}{64 b^4 \sqrt {a^2+2 a b x+b^2 x^2}}-\frac {33 e^2 (d+e x)^{7/2}}{32 b^3 (a+b x) \sqrt {a^2+2 a b x+b^2 x^2}} \]
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Rubi [A] time = 0.19, antiderivative size = 346, normalized size of antiderivative = 1.00, number of steps used = 9, number of rules used = 5, integrand size = 30, \(\frac {\text {number of rules}}{\text {integrand size}}\) = 0.167, Rules used = {646, 47, 50, 63, 208} \begin {gather*} -\frac {33 e^2 (d+e x)^{7/2}}{32 b^3 (a+b x) \sqrt {a^2+2 a b x+b^2 x^2}}-\frac {231 e^3 (d+e x)^{5/2}}{64 b^4 \sqrt {a^2+2 a b x+b^2 x^2}}+\frac {385 e^4 (a+b x) (d+e x)^{3/2}}{64 b^5 \sqrt {a^2+2 a b x+b^2 x^2}}+\frac {1155 e^4 (a+b x) \sqrt {d+e x} (b d-a e)}{64 b^6 \sqrt {a^2+2 a b x+b^2 x^2}}-\frac {1155 e^4 (a+b x) (b d-a e)^{3/2} \tanh ^{-1}\left (\frac {\sqrt {b} \sqrt {d+e x}}{\sqrt {b d-a e}}\right )}{64 b^{13/2} \sqrt {a^2+2 a b x+b^2 x^2}}-\frac {(d+e x)^{11/2}}{4 b (a+b x)^3 \sqrt {a^2+2 a b x+b^2 x^2}}-\frac {11 e (d+e x)^{9/2}}{24 b^2 (a+b x)^2 \sqrt {a^2+2 a b x+b^2 x^2}} \end {gather*}
Antiderivative was successfully verified.
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Rule 47
Rule 50
Rule 63
Rule 208
Rule 646
Rubi steps
\begin {align*} \int \frac {(d+e x)^{11/2}}{\left (a^2+2 a b x+b^2 x^2\right )^{5/2}} \, dx &=\frac {\left (b^4 \left (a b+b^2 x\right )\right ) \int \frac {(d+e x)^{11/2}}{\left (a b+b^2 x\right )^5} \, dx}{\sqrt {a^2+2 a b x+b^2 x^2}}\\ &=-\frac {(d+e x)^{11/2}}{4 b (a+b x)^3 \sqrt {a^2+2 a b x+b^2 x^2}}+\frac {\left (11 b^2 e \left (a b+b^2 x\right )\right ) \int \frac {(d+e x)^{9/2}}{\left (a b+b^2 x\right )^4} \, dx}{8 \sqrt {a^2+2 a b x+b^2 x^2}}\\ &=-\frac {11 e (d+e x)^{9/2}}{24 b^2 (a+b x)^2 \sqrt {a^2+2 a b x+b^2 x^2}}-\frac {(d+e x)^{11/2}}{4 b (a+b x)^3 \sqrt {a^2+2 a b x+b^2 x^2}}+\frac {\left (33 e^2 \left (a b+b^2 x\right )\right ) \int \frac {(d+e x)^{7/2}}{\left (a b+b^2 x\right )^3} \, dx}{16 \sqrt {a^2+2 a b x+b^2 x^2}}\\ &=-\frac {33 e^2 (d+e x)^{7/2}}{32 b^3 (a+b x) \sqrt {a^2+2 a b x+b^2 x^2}}-\frac {11 e (d+e x)^{9/2}}{24 b^2 (a+b x)^2 \sqrt {a^2+2 a b x+b^2 x^2}}-\frac {(d+e x)^{11/2}}{4 b (a+b x)^3 \sqrt {a^2+2 a b x+b^2 x^2}}+\frac {\left (231 e^3 \left (a b+b^2 x\right )\right ) \int \frac {(d+e x)^{5/2}}{\left (a b+b^2 x\right )^2} \, dx}{64 b^2 \sqrt {a^2+2 a b x+b^2 x^2}}\\ &=-\frac {231 e^3 (d+e x)^{5/2}}{64 b^4 \sqrt {a^2+2 a b x+b^2 x^2}}-\frac {33 e^2 (d+e x)^{7/2}}{32 b^3 (a+b x) \sqrt {a^2+2 a b x+b^2 x^2}}-\frac {11 e (d+e x)^{9/2}}{24 b^2 (a+b x)^2 \sqrt {a^2+2 a b x+b^2 x^2}}-\frac {(d+e x)^{11/2}}{4 b (a+b x)^3 \sqrt {a^2+2 a b x+b^2 x^2}}+\frac {\left (1155 e^4 \left (a b+b^2 x\right )\right ) \int \frac {(d+e x)^{3/2}}{a b+b^2 x} \, dx}{128 b^4 \sqrt {a^2+2 a b x+b^2 x^2}}\\ &=\frac {385 e^4 (a+b x) (d+e x)^{3/2}}{64 b^5 \sqrt {a^2+2 a b x+b^2 x^2}}-\frac {231 e^3 (d+e x)^{5/2}}{64 b^4 \sqrt {a^2+2 a b x+b^2 x^2}}-\frac {33 e^2 (d+e x)^{7/2}}{32 b^3 (a+b x) \sqrt {a^2+2 a b x+b^2 x^2}}-\frac {11 e (d+e x)^{9/2}}{24 b^2 (a+b x)^2 \sqrt {a^2+2 a b x+b^2 x^2}}-\frac {(d+e x)^{11/2}}{4 b (a+b x)^3 \sqrt {a^2+2 a b x+b^2 x^2}}+\frac {\left (1155 e^4 \left (b^2 d-a b e\right ) \left (a b+b^2 x\right )\right ) \int \frac {\sqrt {d+e x}}{a b+b^2 x} \, dx}{128 b^6 \sqrt {a^2+2 a b x+b^2 x^2}}\\ &=\frac {1155 e^4 (b d-a e) (a+b x) \sqrt {d+e x}}{64 b^6 \sqrt {a^2+2 a b x+b^2 x^2}}+\frac {385 e^4 (a+b x) (d+e x)^{3/2}}{64 b^5 \sqrt {a^2+2 a b x+b^2 x^2}}-\frac {231 e^3 (d+e x)^{5/2}}{64 b^4 \sqrt {a^2+2 a b x+b^2 x^2}}-\frac {33 e^2 (d+e x)^{7/2}}{32 b^3 (a+b x) \sqrt {a^2+2 a b x+b^2 x^2}}-\frac {11 e (d+e x)^{9/2}}{24 b^2 (a+b x)^2 \sqrt {a^2+2 a b x+b^2 x^2}}-\frac {(d+e x)^{11/2}}{4 b (a+b x)^3 \sqrt {a^2+2 a b x+b^2 x^2}}+\frac {\left (1155 e^4 \left (b^2 d-a b e\right )^2 \left (a b+b^2 x\right )\right ) \int \frac {1}{\left (a b+b^2 x\right ) \sqrt {d+e x}} \, dx}{128 b^8 \sqrt {a^2+2 a b x+b^2 x^2}}\\ &=\frac {1155 e^4 (b d-a e) (a+b x) \sqrt {d+e x}}{64 b^6 \sqrt {a^2+2 a b x+b^2 x^2}}+\frac {385 e^4 (a+b x) (d+e x)^{3/2}}{64 b^5 \sqrt {a^2+2 a b x+b^2 x^2}}-\frac {231 e^3 (d+e x)^{5/2}}{64 b^4 \sqrt {a^2+2 a b x+b^2 x^2}}-\frac {33 e^2 (d+e x)^{7/2}}{32 b^3 (a+b x) \sqrt {a^2+2 a b x+b^2 x^2}}-\frac {11 e (d+e x)^{9/2}}{24 b^2 (a+b x)^2 \sqrt {a^2+2 a b x+b^2 x^2}}-\frac {(d+e x)^{11/2}}{4 b (a+b x)^3 \sqrt {a^2+2 a b x+b^2 x^2}}+\frac {\left (1155 e^3 \left (b^2 d-a b e\right )^2 \left (a b+b^2 x\right )\right ) \operatorname {Subst}\left (\int \frac {1}{a b-\frac {b^2 d}{e}+\frac {b^2 x^2}{e}} \, dx,x,\sqrt {d+e x}\right )}{64 b^8 \sqrt {a^2+2 a b x+b^2 x^2}}\\ &=\frac {1155 e^4 (b d-a e) (a+b x) \sqrt {d+e x}}{64 b^6 \sqrt {a^2+2 a b x+b^2 x^2}}+\frac {385 e^4 (a+b x) (d+e x)^{3/2}}{64 b^5 \sqrt {a^2+2 a b x+b^2 x^2}}-\frac {231 e^3 (d+e x)^{5/2}}{64 b^4 \sqrt {a^2+2 a b x+b^2 x^2}}-\frac {33 e^2 (d+e x)^{7/2}}{32 b^3 (a+b x) \sqrt {a^2+2 a b x+b^2 x^2}}-\frac {11 e (d+e x)^{9/2}}{24 b^2 (a+b x)^2 \sqrt {a^2+2 a b x+b^2 x^2}}-\frac {(d+e x)^{11/2}}{4 b (a+b x)^3 \sqrt {a^2+2 a b x+b^2 x^2}}-\frac {1155 e^4 (b d-a e)^{3/2} (a+b x) \tanh ^{-1}\left (\frac {\sqrt {b} \sqrt {d+e x}}{\sqrt {b d-a e}}\right )}{64 b^{13/2} \sqrt {a^2+2 a b x+b^2 x^2}}\\ \end {align*}
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Mathematica [C] time = 0.05, size = 67, normalized size = 0.19 \begin {gather*} -\frac {2 e^4 (a+b x) (d+e x)^{13/2} \, _2F_1\left (5,\frac {13}{2};\frac {15}{2};\frac {b (d+e x)}{b d-a e}\right )}{13 \sqrt {(a+b x)^2} (b d-a e)^5} \end {gather*}
Antiderivative was successfully verified.
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IntegrateAlgebraic [A] time = 61.19, size = 468, normalized size = 1.35 \begin {gather*} \frac {(-a e-b e x) \left (-\frac {1155 \left (-a^3 e^7+3 a^2 b d e^6-3 a b^2 d^2 e^5+b^3 d^3 e^4\right ) \tan ^{-1}\left (\frac {\sqrt {b} \sqrt {d+e x} \sqrt {a e-b d}}{b d-a e}\right )}{64 b^{13/2} (a e-b d)^{3/2}}-\frac {e^4 \sqrt {d+e x} \left (-3465 a^5 e^5-12705 a^4 b e^4 (d+e x)+17325 a^4 b d e^4-34650 a^3 b^2 d^2 e^3-16863 a^3 b^2 e^3 (d+e x)^2+50820 a^3 b^2 d e^3 (d+e x)+34650 a^2 b^3 d^3 e^2-76230 a^2 b^3 d^2 e^2 (d+e x)-9207 a^2 b^3 e^2 (d+e x)^3+50589 a^2 b^3 d e^2 (d+e x)^2-17325 a b^4 d^4 e+50820 a b^4 d^3 e (d+e x)-50589 a b^4 d^2 e (d+e x)^2-1408 a b^4 e (d+e x)^4+18414 a b^4 d e (d+e x)^3+3465 b^5 d^5-12705 b^5 d^4 (d+e x)+16863 b^5 d^3 (d+e x)^2-9207 b^5 d^2 (d+e x)^3+128 b^5 (d+e x)^5+1408 b^5 d (d+e x)^4\right )}{192 b^6 (a e+b (d+e x)-b d)^4}\right )}{e \sqrt {\frac {(a e+b e x)^2}{e^2}}} \end {gather*}
Antiderivative was successfully verified.
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fricas [B] time = 0.44, size = 968, normalized size = 2.80 \begin {gather*} \left [-\frac {3465 \, {\left (a^{4} b d e^{4} - a^{5} e^{5} + {\left (b^{5} d e^{4} - a b^{4} e^{5}\right )} x^{4} + 4 \, {\left (a b^{4} d e^{4} - a^{2} b^{3} e^{5}\right )} x^{3} + 6 \, {\left (a^{2} b^{3} d e^{4} - a^{3} b^{2} e^{5}\right )} x^{2} + 4 \, {\left (a^{3} b^{2} d e^{4} - a^{4} b e^{5}\right )} x\right )} \sqrt {\frac {b d - a e}{b}} \log \left (\frac {b e x + 2 \, b d - a e + 2 \, \sqrt {e x + d} b \sqrt {\frac {b d - a e}{b}}}{b x + a}\right ) - 2 \, {\left (128 \, b^{5} e^{5} x^{5} - 48 \, b^{5} d^{5} - 88 \, a b^{4} d^{4} e - 198 \, a^{2} b^{3} d^{3} e^{2} - 693 \, a^{3} b^{2} d^{2} e^{3} + 4620 \, a^{4} b d e^{4} - 3465 \, a^{5} e^{5} + 128 \, {\left (16 \, b^{5} d e^{4} - 11 \, a b^{4} e^{5}\right )} x^{4} - {\left (2295 \, b^{5} d^{2} e^{3} - 12782 \, a b^{4} d e^{4} + 9207 \, a^{2} b^{3} e^{5}\right )} x^{3} - {\left (1030 \, b^{5} d^{3} e^{2} + 3795 \, a b^{4} d^{2} e^{3} - 22968 \, a^{2} b^{3} d e^{4} + 16863 \, a^{3} b^{2} e^{5}\right )} x^{2} - {\left (328 \, b^{5} d^{4} e + 748 \, a b^{4} d^{3} e^{2} + 2673 \, a^{2} b^{3} d^{2} e^{3} - 17094 \, a^{3} b^{2} d e^{4} + 12705 \, a^{4} b e^{5}\right )} x\right )} \sqrt {e x + d}}{384 \, {\left (b^{10} x^{4} + 4 \, a b^{9} x^{3} + 6 \, a^{2} b^{8} x^{2} + 4 \, a^{3} b^{7} x + a^{4} b^{6}\right )}}, -\frac {3465 \, {\left (a^{4} b d e^{4} - a^{5} e^{5} + {\left (b^{5} d e^{4} - a b^{4} e^{5}\right )} x^{4} + 4 \, {\left (a b^{4} d e^{4} - a^{2} b^{3} e^{5}\right )} x^{3} + 6 \, {\left (a^{2} b^{3} d e^{4} - a^{3} b^{2} e^{5}\right )} x^{2} + 4 \, {\left (a^{3} b^{2} d e^{4} - a^{4} b e^{5}\right )} x\right )} \sqrt {-\frac {b d - a e}{b}} \arctan \left (-\frac {\sqrt {e x + d} b \sqrt {-\frac {b d - a e}{b}}}{b d - a e}\right ) - {\left (128 \, b^{5} e^{5} x^{5} - 48 \, b^{5} d^{5} - 88 \, a b^{4} d^{4} e - 198 \, a^{2} b^{3} d^{3} e^{2} - 693 \, a^{3} b^{2} d^{2} e^{3} + 4620 \, a^{4} b d e^{4} - 3465 \, a^{5} e^{5} + 128 \, {\left (16 \, b^{5} d e^{4} - 11 \, a b^{4} e^{5}\right )} x^{4} - {\left (2295 \, b^{5} d^{2} e^{3} - 12782 \, a b^{4} d e^{4} + 9207 \, a^{2} b^{3} e^{5}\right )} x^{3} - {\left (1030 \, b^{5} d^{3} e^{2} + 3795 \, a b^{4} d^{2} e^{3} - 22968 \, a^{2} b^{3} d e^{4} + 16863 \, a^{3} b^{2} e^{5}\right )} x^{2} - {\left (328 \, b^{5} d^{4} e + 748 \, a b^{4} d^{3} e^{2} + 2673 \, a^{2} b^{3} d^{2} e^{3} - 17094 \, a^{3} b^{2} d e^{4} + 12705 \, a^{4} b e^{5}\right )} x\right )} \sqrt {e x + d}}{192 \, {\left (b^{10} x^{4} + 4 \, a b^{9} x^{3} + 6 \, a^{2} b^{8} x^{2} + 4 \, a^{3} b^{7} x + a^{4} b^{6}\right )}}\right ] \end {gather*}
Verification of antiderivative is not currently implemented for this CAS.
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giac [B] time = 0.43, size = 548, normalized size = 1.58 \begin {gather*} \frac {1155 \, {\left (b^{2} d^{2} e^{4} - 2 \, a b d e^{5} + a^{2} e^{6}\right )} \arctan \left (\frac {\sqrt {x e + d} b}{\sqrt {-b^{2} d + a b e}}\right )}{64 \, \sqrt {-b^{2} d + a b e} b^{6} \mathrm {sgn}\left ({\left (x e + d\right )} b e - b d e + a e^{2}\right )} - \frac {2295 \, {\left (x e + d\right )}^{\frac {7}{2}} b^{5} d^{2} e^{4} - 5855 \, {\left (x e + d\right )}^{\frac {5}{2}} b^{5} d^{3} e^{4} + 5153 \, {\left (x e + d\right )}^{\frac {3}{2}} b^{5} d^{4} e^{4} - 1545 \, \sqrt {x e + d} b^{5} d^{5} e^{4} - 4590 \, {\left (x e + d\right )}^{\frac {7}{2}} a b^{4} d e^{5} + 17565 \, {\left (x e + d\right )}^{\frac {5}{2}} a b^{4} d^{2} e^{5} - 20612 \, {\left (x e + d\right )}^{\frac {3}{2}} a b^{4} d^{3} e^{5} + 7725 \, \sqrt {x e + d} a b^{4} d^{4} e^{5} + 2295 \, {\left (x e + d\right )}^{\frac {7}{2}} a^{2} b^{3} e^{6} - 17565 \, {\left (x e + d\right )}^{\frac {5}{2}} a^{2} b^{3} d e^{6} + 30918 \, {\left (x e + d\right )}^{\frac {3}{2}} a^{2} b^{3} d^{2} e^{6} - 15450 \, \sqrt {x e + d} a^{2} b^{3} d^{3} e^{6} + 5855 \, {\left (x e + d\right )}^{\frac {5}{2}} a^{3} b^{2} e^{7} - 20612 \, {\left (x e + d\right )}^{\frac {3}{2}} a^{3} b^{2} d e^{7} + 15450 \, \sqrt {x e + d} a^{3} b^{2} d^{2} e^{7} + 5153 \, {\left (x e + d\right )}^{\frac {3}{2}} a^{4} b e^{8} - 7725 \, \sqrt {x e + d} a^{4} b d e^{8} + 1545 \, \sqrt {x e + d} a^{5} e^{9}}{192 \, {\left ({\left (x e + d\right )} b - b d + a e\right )}^{4} b^{6} \mathrm {sgn}\left ({\left (x e + d\right )} b e - b d e + a e^{2}\right )} + \frac {2 \, {\left ({\left (x e + d\right )}^{\frac {3}{2}} b^{10} e^{4} + 15 \, \sqrt {x e + d} b^{10} d e^{4} - 15 \, \sqrt {x e + d} a b^{9} e^{5}\right )}}{3 \, b^{15} \mathrm {sgn}\left ({\left (x e + d\right )} b e - b d e + a e^{2}\right )} \end {gather*}
Verification of antiderivative is not currently implemented for this CAS.
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maple [B] time = 0.07, size = 1471, normalized size = 4.25
result too large to display
Verification of antiderivative is not currently implemented for this CAS.
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maxima [F] time = 0.00, size = 0, normalized size = 0.00 \begin {gather*} \int \frac {{\left (e x + d\right )}^{\frac {11}{2}}}{{\left (b^{2} x^{2} + 2 \, a b x + a^{2}\right )}^{\frac {5}{2}}}\,{d x} \end {gather*}
Verification of antiderivative is not currently implemented for this CAS.
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mupad [F] time = 0.00, size = -1, normalized size = -0.00 \begin {gather*} \int \frac {{\left (d+e\,x\right )}^{11/2}}{{\left (a^2+2\,a\,b\,x+b^2\,x^2\right )}^{5/2}} \,d x \end {gather*}
Verification of antiderivative is not currently implemented for this CAS.
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sympy [F(-1)] time = 0.00, size = 0, normalized size = 0.00 \begin {gather*} \text {Timed out} \end {gather*}
Verification of antiderivative is not currently implemented for this CAS.
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